làm con trai cũng có nhìu cái ko được như con gái đâu kiss_rain_and_you

c/ 2x - 1 = \(5^{98}:5^{96}\)

2x - 1 = \(5^2\) = 25

2x = 25 + 1 = 26

x = 26 : 2

x = 13

d/ 7x + 3 = \(3^5.2^3.9\)

7x + 3 = \(3^5.3^2.8=3^7.8=2187.8\)

7x + 3 = \(17496\)

7x = 17496 - 3 = 17493

x = 17493 : 7

x = 2499

e/\(2^{2x+6}=1\)

\(2^{2x+6}=2^0\)

2x + 6 = 0

2x = 0 - 6 = - 6

x = - 6 : 2

x = - 3

j/ \(2^x=8\)

\(2^x=2^3\)

x = 3

g/ \(2^x:2^3=16\)

\(2^{x-3}=2^4\)

x - 3 = 4

x = 4 + 3

x = 7

h/ \(2^x+2^{x+1}+2^{x+2}=56\)

\(2^x\left(1+2+2^2\right)\) = 56

\(2^x.7=56\)

\(2^x=56:7\)

\(2^x=8\)

\(2^x=2^3\)

x = 3

Bài a, b thiên phong giải r, mk chỉ làm những bài còn lại thôi. Chúc bạn học tốt!!!

a, \(x+2^3=5^2\Rightarrow x+8=25\Rightarrow x=17\)

b, \(2x+3=7^2\Rightarrow2x+3=49\Rightarrow x=\dfrac{49-3}{2}=23\)

Còn lại tự làm.

Mình chỉ ghj đáp za thôj nên thông cảm nha

b)1953368

c)225

d)32

\(a,=4^{10}.4^{10}.4^{45}\)

    \(=4^{65}\)

\(b,=5^9+3^5\)

    \(=1953125+243\)

     \(=1953368\)

\(c,=1+8+27+64+125\)

    \(=225\)

\(d,=32^5:32^4\)

     \(=32\)

\(x^6:x^3=125\)

\(x^3=5^3\)

vậy x = 5

\(x^3=8^2\)

\(x^3=\left(2^3\right)^2=2^6=4^3\)

vậy x = 3

a: \(\dfrac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5+3^5}\cdot\dfrac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5+2^5+2^5+2^5+2^5}=2^x\)

\(\Leftrightarrow2^x=\dfrac{4^5}{3^5}\cdot\dfrac{6^5}{2^5}=4^5=2^{10}\)

=>x=10

b: \(\left(x-1\right)^{x+4}=\left(x-1\right)^{x+2}\)

\(\Leftrightarrow\left(x-1\right)^{x+2}\left[\left(x-1\right)^2-1\right]=0\)

\(\Leftrightarrow x\left(x-1\right)^{x+2}\cdot\left(x-2\right)=0\)

hay \(x\in\left\{0;1;2\right\}\)

c: \(6\left(6-x\right)^{2003}=\left(6-x\right)^{2003}\)

\(\Leftrightarrow5\cdot\left(6-x\right)^{2003}=0\)

\(\Leftrightarrow6-x=0\)

hay x=6

a)

\(\dfrac{7}{5}+\dfrac{5}{6}:5-\dfrac{3}{8}\cdot\left(-3\right)\\ =\dfrac{7}{5}+\dfrac{1}{6}+\dfrac{9}{8}\\ =\dfrac{168+20+135}{120}\\ =\dfrac{323}{120}\)

    ne ban minh biet cau tra loi nhung lam the nao bam ngoac vuong

x=14 nha ban 

Check nhanh cho mk nha m.ng

Bài 1 :

a/   \(a^3.a^9=a^{3+9}=a^{12}\)

b/\(\left(a^5\right)^7=a^{5.7}=a^{35}\)

c/  \(\left(a^6\right).4.a^{12}=a^{24}.a^{12}.4=a^{24+12}.4=a^{36}.4\)

d/  \(\left(2^3\right)^5.\left(2^3\right)^3=2^{15}.2^9=2^{15+9}=2^{24}\)

e/  \(5^6:5^3+3^3.3^2\)

     \(=5^3+3^5=125+243=368\)

i/ \(4.5^2-2.3^2\)

   \(=2^2.5^2-2.3^2\)

   \(=2^2.25-2^2.14\)

   \(=2^2.\left(25-14\right)\)

   \(=2^2.11\)      

   \(=4.11=44\)

Bài 2 :

a, \(3^8:3^6=3^{8-6}=3^2\)

 \(7^5:7^2=7^{5-2}=7^3\)

 \(19^7:19^3=19^{7-3}=19^4\)

  \(2^{10}.8^3=2^{10}.\left(2^3\right)^3=2^{10}.2^9=2^{19}\)  

\(12^7:6^7=\left(12:6\right)^7=2^7=128\)

\(27^5:81^3=\left(3^3\right)^5:\left(3^4\right)^3=3^{15}:3^{12}=3^3=9\)