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Bài làm
a) \(\left(\frac{1}{2}+\frac{4}{7}\right)-\left(\frac{3}{7}-\frac{3}{10}\right)\)
\(=\frac{1}{2}+\frac{4}{7}-\frac{3}{7}+\frac{3}{10}\)
\(=\frac{35}{70}+\frac{40}{70}-\frac{30}{70}+\frac{21}{70}\)
\(=\frac{66}{70}\)
\(=\frac{33}{35}\)
b) \(\left(\frac{3}{5}x\frac{4}{5}x\frac{5}{9}\right):\left(\frac{7}{9}-\frac{3}{5}\right)\)
\(=\left(\frac{1}{5}x\frac{4}{3}\right):\left(\frac{35}{45}-\frac{27}{45}\right)\)
\(=\frac{4}{15}:\frac{8}{45}\)
\(=\frac{4}{15}.\frac{45}{8}\)
\(=\frac{1}{1}.\frac{3}{2}\)
\(=\frac{3}{2}\)
a, 9/1 * 3/8 + 3/8 * 9/7
b, 4/5 * 7/10 - 1/9 * 4/5
C1:nhân chia trước cộng trừ sau
C2:a,3,8x(9,1+9,7)=3,8x18,8=?
b,b, 4/5 * 7/10 - 1/9 * 4/5=4/5x(7/10-1/9)=?
A =\(\frac{2}{5}\times\frac{4}{7}+\frac{3}{5}\times\frac{4}{7}\) B = \(\frac{17}{13}\times\frac{12}{17}-\frac{4}{13}\times\frac{12}{17}\) C = \(\frac{9}{14}:\frac{6}{7}+\frac{5}{14}:\frac{6}{7}\) D =\(\frac{9}{12}:\frac{7}{9}\times\frac{12}{19}\)
= \(\frac{4}{7}\times\left(\frac{2}{5}+\frac{3}{5}\right)\) =\(\left(\frac{17}{13}-\frac{4}{13}\right)\times\frac{12}{17}\) = \((\frac{9}{14}+\frac{5}{14}):\frac{6}{7}\) = \(\frac{9}{12}\times\frac{9}{7}\times\frac{12}{19}\)
=\(\frac{4}{7}\times1\) = \(1\times\frac{12}{17}\) = \(1:\frac{6}{7}\) = \(\frac{9\times9\times12}{12\times7\times19}\)
=\(\frac{4}{7}\) = \(\frac{12}{17}\) =\(\frac{7}{6}\) = \(\frac{9\times9}{7\times19}=\frac{81}{133}\)
a] 4/12 ; 5/12 ; 11/2 ; 1/4
b] 1 ; 9/12; 12/5 ; 11/3
c] 8/21; 6/11;8/7
d] 2/3 ;2/7 15/2
a]1/3 5/12 11/2 1/4
b]1 3/4 12/5 33/9
c]8/21 6/11 8/7
d]2/3 2/7 15/2
A) 3\7 + 5\9 +4\7+ 4\9=(3\7+4\7) + ( 5\9 +4\9) = 7\7+9\9=63\63+63\63=126\63=42\21
b) 1\5+4\11+4\5+ 7\11=(1\5+4\5)+ (4\11+7\11)=5\5+11\11=55\55+55\55=110\55=22\11
1, =4/9 x (3/7 + 2 x 4/7) - 1/9 - 3/9
= 4/9 x 1 - 1/9 - 3/9 = 0
2, = ( 22/5 x 5/22 ) x 12
= 1 x 12 = 12
2/9+3/9+4/9+5/9+6/9+7/9
=2+3+4+5+6+7/9
=27/9
=3
1/6+4/9+5/6+11/16+5/9+5/16
=1/6+5/6+4/9+5/9+11/16+5/16
=1+1+1=3
hok tốt ~
Lời giải:
a.
$\frac{4}{7}+\frac{5}{9}=\frac{4\times 9}{7\times 9}+\frac{5\times 7}{9\times 7}$
$=\frac{36}{63}+\frac{35}{63}=\frac{71}{63}$
b.
$\frac{9}{5}-\frac{4}{7}=\frac{9\times 7}{5\times 7}-\frac{4\times 5}{7\times 5}$
$=\frac{63}{35}-\frac{20}{35}=\frac{43}{35}$
a)4/7+5/9
=36/63+35/63
= 71/63
B)9/5-4/7
=63/35-20/35
=43/35