(x+1)+(x+2)+(x+3)+...+(x+99)+(x+100)=50

100x+5050=50

100x=-5000

x=-50

\(c,\)\(\left(x-1\right)+\left(x-2\right)+....+\left(x-100\right)=50\)

\(\left(x+x+...+x\right)-\left(1+2+...+100\right)=50\)

\(100x-5050=50\)

\(100x=50+5050\)

\(100x=5100\)

\(\Rightarrow x=\frac{5100}{100}=51\)

\(a,\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+....+\left(x+100\right)=5750\)

\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)

\(100x+5050=5750\)

\(100x=5750-5050\)

\(100x=700\)

\(\Rightarrow x=7\)

\(b,x+\left(1+2+3+...+50\right)=2000\)

 \(x+\frac{\left[1+50\right]\cdot\left[\left(50-1\right)\div1+1\right]}{2}=2000\)

\(x+1275=2000\)

\(\Rightarrow x=2000-1275=725\)

=> X x ( 1+2+3+4+....+50) = 2 x ( 1+2+3+...+50)

=> x=2

αi nhanh mình sẽ Tick ạ.

A = \(\dfrac{3^{100}.\left(-2\right)+3^{101}}{\left(-3\right)^{101}-3^{100}}\) 

A = \(\dfrac{3^{100}.\left(-2\right)+3^{100}.3}{\left(-3\right)^{100}.\left(-3\right)-3^{100}}\)

A = \(\dfrac{3^{100}.\left(-2+3\right)}{3^{100}.\left(-3\right)-3^{100}}\)

A = \(\dfrac{3^{100}.1}{3^{100}.\left(-3-1\right)}\)

A = \(\dfrac{3^{100}}{3^{100}}\) . \(\dfrac{1}{-4}\)

A = - \(\dfrac{1}{4}\)

A.   \(\left(x+1\right)+\left(x+2\right)+......+\left(x+100\right)=5750\)

      \(x+1+x+2+....+x+100=5750\)

      \(100x+\left(1+2+3+.......+100\right)=5750\)

      \(100x+5050=5750\)

\(100x=700\)

\(x=700:100=7\)

B.   x+(1+2+......+100) = 2000

       x + 5050 = 2000

            x = 2000 - 5050

           x= -3050

C.   ( x-1 )+(x-2)+......+( x - 100 ) = 50

 x-1+x-2+.........+x-100 = 50

100x + ( -1-2-........-100  ) = 50

100x + ( - 5050 ) = 50

100x = 50 + 5050

100 x = 5100

x = 5100 : 100

x = 51

A . \(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)

\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)

\(100x+5050=5750\)

\(100x=5750-5050\)

\(100x=700\)

\(\Rightarrow x=\frac{700}{100}=7\)

B. \(x+\left(1+2+3+4+5+....+100\right)=2000\)

 \(x+\frac{\left(100+1\right).100}{2}=2000\)

\(x+5050=2000\)

\(\Rightarrow x=2000-5050=-3050\)

C. \(\left(x-1\right)+\left(x-2\right)+\left(x-3\right)+....+\left(x-100\right)=50\)

\(\left(x+x+x+...+x\right)-\left(1+2+3+...+100\right)=50\)

\(100x-5050=50\)

\(100x=5100\)

\(\Rightarrow x=\frac{5100}{100}=51\)

a) x . (x - 1) = 0

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x+1=1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=0+1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)

b) (x - 1)² = 100 

<=> (x - 1)² = 10²

\(\Leftrightarrow\orbr{\begin{cases}x-1=10\\x-1=-10\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=10+1\\x=-10+1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=11\\x=-9\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=11\\x=-9\end{cases}}\)

a,\(x\left(x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)

b,\(\left(x-1\right)^2=100\)

\(\Rightarrow\orbr{\begin{cases}x-1=10\\x-1=-10\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=11\\x=-9\end{cases}}\)

c,\(x^{50}=x^2\)

\(\Rightarrow x^{50}-x^2=0\)

\(\Rightarrow x^2\left(x^{48}-1\right)=0\)

\(\Rightarrow\hept{\begin{cases}x=0\\x=\pm1\end{cases}}\)