a) \(\left(2017\times2018+2018+2019\right)\times\left(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)\)

\(=\left(2017\times2018+2018+2019\right)\times\left(1+\frac{1}{2}:\frac{3}{2}-1\frac{1}{3}\right)\)

\(=\left(2017\times2018+2018+2019\right)\times\left(1+\frac{1}{3}-1\frac{1}{3}\right)\)

\(=\left(2017\times2018+2018+2019\right)\times0\)

\(=0\)

b) 10,11 + 11,12 + 12,13 + ...+ 98,99 + 99, 100

Số số hạng từ 10,11 đến 98,99 là:

( 98,99 - 10,11) : 1,01 + 1= 89

Tổng dãy số trên từ 10,11 đến 98,99 là:

( 98,99 + 10,11) x 89 : 2 = 4 854,95

=> 10,11 + 11,12+12,13 + ...+ 98,99+ 99,100 = 4 854,95 + 99, 1 = 4 954, 05

a) ( 2017 * 2018 + 2018 +2019) * (1 + 1/2 : 1   1/2 - 1   1/3)

    ( 2017 * 2018 + 2018 +2019) * (1 + 1/2 : 3/2 -4/3)

    ( 2017 * 2018 + 2018 * 1 +2019) * (1 + 1/3 -4/3 )

   [ ( 2017 +1) * 2018 +2019)] * ( 4/3 - 4/3)

   ( 2018 * 2018 + 2019 )    *      0

  ( 4072324 + 2019)           *      0

    4074343                      *         0

= 0

a)\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.\frac{4}{5}......\frac{99}{100}\)

\(=\frac{1.2.3.4.....99}{2.3.4.5.6.....100}\)

\(=\frac{1}{100}\)

b) Tương tự như câu a

Ra kết quả phần b là \(\frac{101}{2}\) đúng hông?

ko ghi lại đề 

ta thấy : 2019 - 1 = 2018 

2020 - 2 = 2018 

2021 - 3 = 2018 

2022 - 4 = 2018 

=> x = 2018

thử lại :

2018+1/2019 + 2018+2/2020 = 2018+3/2021 + 2018+4/2022

= 1 + 1 = 1 + 1

2 = 2

2020 - 2 = 2018 
2021 - 3 = 2018 
2022 - 4 = 2018 
=> x = 2018

thây zô mà thử lại

\(1\frac{1}{2}.1\frac{1}{3}.1\frac{1}{4}...1\frac{1}{9}\)

\(=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}...\frac{10}{9}\)

\(=\frac{10}{2}=5\)

DẤU . LÀ DẤU NHÂN NHA BẠN

\(1\frac{1}{2}\times1\frac{1}{3}\times1\frac{1}{4}\times1\frac{1}{5}\times1\frac{1}{6}\times1\frac{1}{7}\times1\frac{1}{8}\times1\frac{1}{9}\)

\(=\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\times\frac{6}{5}\times\frac{7}{6}\times\frac{8}{7}\times\frac{9}{8}\times\frac{10}{9}\)

\(=\frac{3\times4\times5\times6\times7\times8\times9\times10}{2\times3\times4\times5\times6\times7\times8\times9}=\frac{10}{2}=5\)

~ Hok tốt ~

\(\left(2746-x\right)-258=1360\)

\(2746-x=1360+258\)

\(2746-x=1618\)

\(x=2746-1618\Rightarrow x=1128\)

Ta có : \(\frac{1}{4}+\frac{1}{3}:\frac{1}{x}=\frac{11}{12}\)

\(\Rightarrow\frac{1}{3}:\frac{1}{x}=\frac{11}{12}-\frac{1}{4}\)

\(\frac{1}{3}:\frac{1}{x}=\frac{2}{3}\)

\(\frac{1}{x}=\frac{1}{3}:\frac{2}{3}\)

\(\frac{1}{x}=\frac{1}{3}\times\frac{3}{2}\)

\(\frac{1}{x}=\frac{1}{2}\)

=> x = 2

a) \(\frac{x\div3-16}{2}+21=38\)

\(\frac{x\div3-16}{2}=38+21\)

\(\frac{x\div3-16}{2}=59\)

\(x\div3-16=59.2\)

\(x\div3-16=118\)

\(x\div3=118+16\)

\(x\div3=134\)

\(x=134.3\)

\(x=402\)

b) \(\frac{1}{4}+\frac{1}{3}\div\frac{1}{x}=\frac{11}{12}\)

\(\frac{1}{3}\div\frac{1}{x}=\frac{11}{12}-\frac{1}{4}\)

\(\frac{1}{3}\div\frac{1}{x}=\frac{2}{3}\)

\(\frac{1}{x}=\frac{1}{3}\div\frac{2}{3}\)

\(\frac{1}{x}=\frac{1}{2}\)

Vậy x = ....

Câu b

Ta có :x + 3 /1.3  +3/3.5 + 3/5.7+...+3/13.15=2 1/5

X + 2/3.(1-1/3+1/3-1/5+1/5-1/7+...+1/13-1/15)1=11/5

X+2/3.(1-1/15)=11/5

X+ 2/3.14/15=11/5

X + 28/45=11/5

X = 11/5 -28/45

X=71/45

Câu a  gợi ý 

1/2-1/3/1/6=0 

1/2- 1/3 - 1/6 ) x (1/2 + 2/3 + 3/4 +4/5 + .......+ 2019 /2020 ) =0 

3/4:x=9/10

X = 3/4:9/10

X = 5/6

 \(\dfrac{3}{4}\times\dfrac{8}{5}:1\dfrac{1}{6}\) 

=\(\dfrac{6}{5}:\) \(\dfrac{7}{6}\) 

=\(\dfrac{6}{5}\times\dfrac{6}{7}=\dfrac{36}{35}\)

2\(\dfrac{1}{3}\) x 1\(\dfrac{1}{4}\) -\(\dfrac{7}{5}\)

\(\dfrac{7}{3}\times\dfrac{5}{4}-\) \(\dfrac{7}{5}\) 

\(\dfrac{35}{12}-\dfrac{7}{5}\)

\(\dfrac{175}{60}-\dfrac{84}{60}=\dfrac{91}{60}\)

4\(\dfrac{2}{3}+1\dfrac{1}{4} +2\dfrac{1}{3}+2\dfrac{3}{7}\)

(4 +2) + \(\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\) +1\(\dfrac{1}{4}\) + \(2\dfrac{3}{7}\) 

6 + 1 + \(\dfrac{5}{4}\) + \(\dfrac{17}{7}\)

7 + \(\dfrac{103}{28}\)

\(\dfrac{299}{28}\)