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\(S=3+3^2+3^3+...........+3^{100}\)
\(\Leftrightarrow\)\(3S=3^2+3^3+3^4+...........+3^{101}\)
\(\Leftrightarrow\)\(3S-S=3^{101}-3\)
\(\Leftrightarrow\)\(2S=3^{101}-3\)
\(\Leftrightarrow\)\(S=\frac{3^{101}-3}{2}\)
Vậy \(S=\frac{3^{101}-3}{2}\)
a)A=(2+22)+(23+24)+...(29+210)
A=2(2+1)+23(1+2)+....+29(2+1)
A=3(2+23+25+27+29)
Vay A chia het cho 3(khi chia 3 duoc 2+23+25+27+29du 0)
b)A=(2+22+23+24+25)+(26+27+28+29+210)
A=2(1+2+22+23+24)+26(1+2+22+23+24)
A=31(2+26) luon chia het cho 31 :))
3x - 23 = 32 + 114
=> 3x - 8 = 9 + 1
=> 3x - 8 = 10
=> 3x = 18
=> x = 6
vậy_
1)\(3x-2^3=3^2+1^{14}=9+1=10\)\(10\)
\(\Rightarrow3x-8=10\Rightarrow3x=10+8=18\)
\(\Rightarrow x=18:3=6\)
2)\(2^5x-3^3x=121-\frac{15}{15}\)
\(\Rightarrow x.\left(2^5-3^3\right)=121-1\)
\(\Rightarrow x.5=120\Rightarrow x=120:5=24\)
B = 1 + 4 + 42 +...+ 4200 + 4201
=> 4B = 4 + 42 +43 +...+ 4201 + 4202
=> 4B-B = 4202 - 1
3B = 4202 -1
\(\Rightarrow B=\frac{4^{202}-1}{3}\)
4B = 4 + 4^2 + 4^3 + ... + 4^202
4B - B = ( 4 + 4^2 + 4^3 + ... + 4^202 ) - ( 1 + 4 + 4^2 + ... + 4^201 )
3B = 4^202 - 1
B = \(\frac{4^{202}-1}{3}\)
1024 : ( 14 . 25 + 15 . 25)
1024 : [ 25 . ( 14 + 15 ) ]
1024 : [ 25 . 29 ]
1024 : [ 32 . 29 ]
1024 : 928
32/29
1024: (14x \(2^5\)+15x \(^{2^5}\)) = 1024: (14+15x \(^{2^5}\))
=1024: (29 x 32)
=1024:928
=\(\frac{32}{29}\)
a, [ 13-17 ].[-10]+[-7]0
=-4.[-10]+1
=40+1
=41
b, 72.[28-49] + 28.[-49-72]
=72.[-21]+28.[-121]
=-1512+[-3388]
=-4900
c, -65.[87-17] - 87.[17-65]
=-65.70-87.[-48]
=4550-[-4276]
=8726
d, -23.63+23.21-58.23
=23.(-63)+23.21-58.23
=23.(-63+23-58)
=23.(-40-58)
=23.(-98)
=-2254
e, 25.134+25.[-34]
=25.[134+(-34)]
=25.100
=2500
10.|3x2-17|=100
=> |3x2-17|=10
\(\Rightarrow\orbr{\begin{cases}3x^2-7=10\\3x^2-7=-10\end{cases}\Leftrightarrow\orbr{\begin{cases}3x^2=17\\3x^2=-3\end{cases}}}\Leftrightarrow\orbr{\begin{cases}x=\sqrt{\frac{17}{3}}\\x=1\end{cases}}\)
Học tốt
\(10\cdot\left|3x^2-17\right|=100\)
\(\Leftrightarrow\left|3x^2-17\right|=10\)
\(\Leftrightarrow\orbr{\begin{cases}3x^2-17=10\\3x^2-17=-10\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}3x^2=27\\3x^2=7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x^2=9\\x^2=\frac{7}{3}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\pm3\\x=\pm\frac{\sqrt{7}}{\sqrt{3}}\end{cases}}\)