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\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}+\frac{1}{3}\right)=\frac{4}{5}.\frac{3}{3}=\frac{4}{5}.1=\frac{4}{5}\)
\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}+\frac{1}{6}\right)=\frac{3}{4}:\frac{2}{3}=\frac{9}{8}\)
\(\frac{2}{3}.\frac{4}{5}-\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}-\frac{1}{3}\right)=\frac{4}{5}.\frac{1}{3}=\frac{4}{15}\)
\(\frac{1}{2}:\frac{3}{4}-\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}-\frac{1}{6}\right)=\frac{3}{4}:\frac{1}{3}=\frac{9}{4}\)
\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\left(\frac{2}{3}+\frac{1}{3}\right).\frac{4}{5}=1.\frac{4}{5}=\frac{4}{5}\)
\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{1}{2}.\frac{4}{3}+\frac{1}{6}.\frac{4}{3}=\left(\frac{1}{2}+\frac{1}{6}\right).\frac{4}{3}=\frac{2}{3}.\frac{4}{3}=\frac{8}{9}\)
c,d tương tự
\(\frac{2}{3}\times\frac{3}{4}\times\frac{4}{5}=\frac{2}{5}\)
\(\frac{1}{2}:\frac{3}{4}:\frac{5}{6}=\frac{1}{2}\times\frac{4}{3}\times\frac{6}{5}=\frac{1\times2\times2}{5}=\frac{4}{5}\)
a)=1/10+1/10+1/10+1/10+1/10+1/10+1/10+1/10+1/10
=1/10*9
=9/10
b)=(3,72+6,28)+(2,05+7,95)
=10+10
=20
a) \(\frac{8}{11}-\frac{28}{99}-\frac{14}{99}=\frac{72}{99}-\frac{28}{99}-\frac{14}{99}=\frac{30}{99}=\frac{10}{33}\)
b) \(5\frac{3}{4}-3\frac{1}{2}=\)\(\frac{23}{4}-\frac{7}{2}=\frac{23}{4}-\frac{14}{4}=\frac{9}{4}\)
A) 8/11- 28/99- 14/99 8/11=72/99 (72/99 +28/99)-14/99 =100/99-14/99 =86/99
b)\(\left(2016.1017+2017.2018\right).\left(1+\frac{1}{2}:\frac{3}{2}-\frac{4}{3}\right)\)
\(\left(2016.2017+2017.2018\right)\left(1+\frac{1}{3}-\frac{4}{3}\right)\)
\(\left(2016.2017+2017.2018\right).\left(\frac{4}{3}-\frac{4}{3}\right)\)
\(\left(2016.2017+2017.2018\right).0\)
\(=0\)
c) \(\frac{3}{5}+\frac{3}{4}+\frac{2}{5}+\frac{5}{8}+\frac{1}{2}\)
= \(\frac{3}{5}+\frac{2}{5}+\left(\frac{6}{8}+\frac{5}{8}+\frac{4}{8}\right)\)
= 1 + \(\frac{15}{8}\)
= 2\(\frac{7}{8}\)
3/5+3/4+2/5+5/8+1/2
=(3/5+2/5)+(3/4+1/2)+5/8
=1+5/4+5/8
=1+15/8=23/8
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a \(\frac{4}{18}+\frac{5}{13}+\frac{7}{9}+\frac{21}{13}\)
= \(\left(\frac{4}{18}+\frac{7}{9}\right)+\left(\frac{5}{13}+\frac{21}{13}\right)\)
= \(1+2\)
= \(3\)
b \(\frac{4}{3}-\frac{2}{7}-\frac{5}{7}+\frac{2}{3}\)
= \(\left(\frac{4}{3}-\frac{2}{3}\right)-\left(\frac{2}{7}+\frac{5}{7}\right)\)
= \(\frac{2}{3}-1\)
= \(-\frac{1}{3}\)
Có j khó đâu bạn,chịu khó một chút là được thui
khó là khó