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29 tháng 6 2018

\(1\hept{\begin{cases}6x^2-8x+3x-4\\2x\left(3x-4\right)+\left(3x-4\right)\\\left(3x-4\right)\left(2x+1\right)\end{cases}}\)

\(2\hept{\begin{cases}7x^2-7xy-5x+5y+6xy\\7x\left(x-y\right)-5\left(x-y\right)+\frac{6xy\left(x-y\right)}{\left(x-y\right)}\\\left(x-y\right)\left(7x-5+\frac{6xy}{\left(x-y\right)}\right)\end{cases}}\)

\(3\hept{\begin{cases}5x\left(x-y\right)-15\left(x-y\right)\\\left(x-y\right)\left(5x-15\right)\end{cases}}\)

\(4,,2x^2+x=x\left(2x+1\right)\)

\(5\hept{\begin{cases}x^3-4x-3x^2+12\\x\left(x^2-4\right)-3\left(x^2-4\right)\\\left(x+2\right)\left(x-2\right)\left(x-3\right)\end{cases}}\)

\(6\hept{\begin{cases}2x+2y+x^2-y^2\\2\left(x+y\right)+\left(x+y\right)\left(x-y\right)\\\left(x+y\right)\left(2+x-y\right)\end{cases}}\)

\(7\hept{\begin{cases}\left(x^2y-2xy\right)-\left(xy-2y\right)+\left(xy-y\right)\\xy\left(x-2\right)-y\left(x-2\right)+y\left(x-1\right)\\y\left(X-2\right)\left(x-1\right)+y\left(x-1\right)\end{cases}}\Leftrightarrow y\left(x-1\right)\left(x-2+1\right)\)

\(8\hept{\begin{cases}x\left(2-y\right)+z\left(2-y\right)\\\left(2-y\right)\left(x+1\right)\end{cases}}\)

16 tháng 9 2018

\(2x^2+x\)

\(=x\left(2x+1\right)\)

.

hk 

tốt

28 tháng 6 2017

Phép trừ các phân thức đại số

11 tháng 10 2017

1)

a) \(x^2-xy+x-y=x\left(x-y\right)+\left(x-y\right)=\left(x-y\right)\left(x+1\right)\)

b) \(xz+yz-5\left(x+y\right)=z\left(x+y\right)-5\left(x+y\right)=\left(x+y\right)\left(z-5\right)\)

c) \(3x^2-3xy-5x+5y=\left(3x^2-3xy\right)-\left(5x-5y\right)=3x\left(x-y\right)-5\left(x-y\right)=\left(x-y\right)\left(3x-5\right)\)

11 tháng 10 2017

Bài 2:

a) \(x^2+4x-y^2+4=\left(x^2+2\cdot x\cdot2+2^2\right)-y^2=\left(x+2\right)^2-y^2=\left(x-y+2\right)\left(x+y+2\right)\)

b) \(3x^2+6xy+3y^2-3z^2=3\left(x^2+2xy+y^2-z^2\right)=3\left[\left(x+y\right)^2-z^2\right]=3\left(x+y-z\right)\left(x+y+z\right)\)

c) \(x^2-2xy+y^2-z^2+2zt-t^2=\left(x-y\right)^2-\left(z-t\right)^2=\left(x-y-z+t\right)\left(x-y+z-t\right)\)

\(1.\)

\(4x^2-12x+9\)

\(=\left(2x\right)^2-12x+3^2=\left(2x-3\right)^2\)

\(2.\)

\(7x^2-7xy-5x+5y\)

\(=7x\left(x-y\right)-5\left(x-y\right)\)

\(\left(7x-5\right)\left(x-y\right)\)

\(3.\)

\(x^3-9x\)

\(=x\left(x^2-9\right)\)

\(=x\left(x-3\right)\left(x+3\right)\)

\(4.\)

\(5x\left(x-y\right)-15\left(x-y\right)\)

\(=\left(5x-15\right)\left(x-y\right)\)

\(=5\left(x-3\right)\left(x-y\right)\)

\(5.\)

\(2x^2+x\)

\(=2x\left(x+1\right)\)

\(6.\)

\(x^3+27\)

\(=\left(x+3\right)\left(x^2-3x+9\right)\)

\(7.\)

\(2x^2-4xy+2y^2-32\)

\(=2\left(x^2-2xy+y^2-16\right)\)

\(=2\left[\left(x^2-2xy+y^2\right)-16\right]\)

\(=2\left[\left(x-y\right)^2-4^2\right]\)

\(=2\left(x-y+4\right)\left(x-y-4\right)\)

\(8.\)

\(x^3-4x-3x^2+12\)

\(=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)

\(9.\)

\(2x+2y+x^2-y^2\)

\(=2\left(x+y\right)+\left(x-y\right)\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y+2\right)\)

\(10.\)

\(x^2y-2xy+y\)

\(=y\left(x^2-2x+1\right)\)

\(=y\left(x-1\right)^2\)

\(11.\)

\(y^2+2y\)

\(=y\left(y+2\right)\)

\(12.\)

\(y^2-x^2-6y-6x\)

\(=\left(y-x\right)\left(y+x\right)-6\left(y+x\right)\)

\(=\left(y+x\right)\left(y-x-6\right)\)

\(13.\)

\(x^3-3x\)

\(=x\left(x^2-3\right)\)

\(=x\left(x-\sqrt{3}\right)\left(x+\sqrt{3}\right)\)

\(14.\)

\(2x-xy+2z-yz\)

\(=x\left(2-y\right)+z\left(2-y\right)\)

\(=\left(2-y\right)\left(x+z\right)\)

Xong

4 tháng 7 2018

cảm ơn nhiều lắm

Câu 2 nha

\(a,x^4+2x^3+x^2\)

\(=x^2\left(x^2+2x+1\right)\)

\(=x^2\left(x+1\right)^2\)

\(c,x^2-x+3x^2y+3xy^2+y^3-y\)

\(=\left(x^3+3x^2y+3xy^2+y^3\right)-\left(x+y\right)\)

\(=\left(x+y\right)^3-\left(x+y\right)\)

\(=\left(x+y\right)\left(x^2+2xy+y^2-1\right)\)

20 tháng 4 2017

Bài giải:

a) x2 – xy + x – y = (x2 – xy) + (x - y)

= x(x - y) + (x -y)

= (x - y)(x + 1)

b) xz + yz – 5(x + y) = z(x + y) - 5(x + y)

= (x + y)(z - 5)

c) 3x2 – 3xy – 5x + 5y = (3x2 – 3xy) - (5x - 5y)

= 3x(x - y) -5(x - y) = (x - y)(3x - 5).

28 tháng 6 2017

\(a) x^2 - xy+x-y\) \(= (x^2 - xy) + ( x- y) \)

\(=x(x-y) + (x-y)\)

\(= (x-y) (x+1)\)

\(b) xz + yz - 5(x+y)\) \(= (xz + yz) - 5(x+y)\)

\(= z(x+y) - 5(x+y)\)

\(= (x+y) (z-5)\)

\(c) 3x^2 - 3xy - 5x +5y = (3x^2-3xy) - (5x-5y)\)

\(= 3x(x-y) - 5(x-y)\)

\(= (x-y)(3x-5)\)

29 tháng 6 2018

Bài nhiều quá... nhìn mik nổi gai ốc lun...oh my god sao mà nhiều vậy nè .

Mik định giải giúp bạn nhưng bây h mik hoảng quá ... nhiều vậy chắc mik chết mất... ToT ... >.<  =)))

30 tháng 6 2018

2x2 + x 

= x (2x + x)

13 tháng 10 2019

\(e,-5x+x^2-14\)

\(=x^2+2x-7x-14\)

\(=x\left(x+2\right)-7\left(x+2\right)\)

\(=\left(x+2\right)\left(x-7\right)\)

\(f,x^3+8+6x\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2+2x+4\right)+6x\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2+8x+4\right)\)

\(g,15x^2-7xy-2y^2\)

\(=15x^2+3xy-10xy-2y^2\)

\(=3\left(5x+y\right)-2y\left(5x+y\right)\)

\(=\left(5x+y\right)\left(3-2y\right)\)

\(h,3x^2-16x+5\)

\(=3x^2-x-15x+5\)

\(=x\left(3x-1\right)+5\left(3x-1\right)\)

\(=\left(3x-1\right)\left(x+5\right)\)

13 tháng 10 2019

\(a,x^3+2x^2y+xy^2=x\left(x^2+2xy+y^2\right)\)

\(=x\left(x+y\right)^2\)

\(b,4x^2-9y^2+4x-6y\)

\(=4x^2+4x+1-\left(9y^2+6y+1\right)\)

\(=\left(2x+1\right)^2-\left(3y+1\right)^2\)

\(=\left(2x-3y\right)\left(2x+3y+2\right)\)

\(c,-x^2+5x+2xy-5y-y^2\)

\(=-\left(x^2-2xy+y^2\right)+5\left(x-y\right)\)

\(=-\left(x-y\right)^2+5\left(x-y\right)\)

\(=\left(x-y\right)\left(y-x+5\right)\)

\(d,x^2+4x-12\)

\(=x^2-2x+6x-12\)

\(=x\left(x-2\right)+6\left(x-2\right)\)

\(=\left(x-2\right)\left(x+6\right)\)

27 tháng 10 2021

helpppppp

27 tháng 3 2020
https://i.imgur.com/zwAtPMZ.jpg