1313/1717 = ( 1313 :101)/(1717:101)=13/17

171717/191919=(171717:10101)/(191919:10101)=17/19

231231/343343=(231231:7007)/(343343:7007)=33/49

373737/494949=(373737:10101)/(494949:10101)=37/49

a)Ta có: \(\frac{1313}{1515}< \frac{1313}{1428}< \frac{1326}{1428}\Rightarrow\frac{1313}{1515}< \frac{1326}{1428}\)

b)Ta có: \(1-\frac{119}{120}=\frac{1}{120}< 1-\frac{118}{119}=\frac{1}{119}\Rightarrow\frac{119}{120}>\frac{118}{119}\)

c)Ta có: \(\frac{222}{555}< \frac{222}{444}< \frac{333}{444}\Rightarrow\frac{222}{555}< \frac{333}{444}\)

A) <

b) >

c) =

Tổng của ba phân số đó là : \(\left(\frac{31}{24}+\frac{7}{8}+\frac{11}{12}\right)\div2=\frac{37}{24}\)

Phân số thứ nhất là : \(\frac{37}{24}-\frac{7}{8}=\frac{2}{3}\)

Phân số thứ hai là : \(\frac{37}{24}-\frac{11}{12}=\frac{5}{8}\)

Phân số thứ ba là : \(\frac{37}{24}-\frac{31}{24}=\frac{1}{4}\)

#Death.Hunter

Ta có: \(\frac{1212}{1313}=\frac{12x101}{13x101}=\frac{12}{13}\)

Vậy \(\frac{12}{13}=\frac{1212}{1313}\)

Ta có: 1212/1313 = 12.101/13.101= 12/13

Vì 12/13 = 12/13 nên 12/13 = 1212/1313

Vây...

1313/3737 rút gọn thành 13/37

13/37=0,(351)

1717/4141 rút gọn thành 17/41

17/41=0,(41463)

vì 0,(351)<0,(41463) suy ra 13/37<17/41

Ta có:

\(\frac{2017.2019}{2018.2018}\)

\(=\frac{2017.\left(2018+1\right)}{\left(2017+1\right).2018}\)

\(=\frac{2017.2018+2017}{2017.2018+2018}\)

Vì \(2017.2018+2017< 2017.2018+2018\)( tử nhỏ hơn mẫu )

\(\Rightarrow\frac{2017.2018+2017}{2017.2018+2018}< 1\)

Vậy \(\frac{2017.2019}{2018.2018}< 1\)

        ( Mk nghĩ vậy )

                          ~~~~~~~Hok tốt~~~~~~~

\(\frac{2017.2019}{2018.2018}=\frac{2017.\left(2018+1\right)}{2018.\left(2017+1\right)}=\frac{2017.2018+2017}{2018.2017+2018}\)

\(2017< 2018\Rightarrow2017.2018+2017< 2018.2017+2018\Rightarrow\frac{2017.2018+2017}{2018.2017+2018}< 1\Rightarrow\frac{2017.2019}{2018.2018}< 1\)