Theo mình là : \(A< B\)

\(A=1-\frac{1}{2014x2015}\)

\(B=1-\frac{1}{2015x2016}\)

\(2014x2015< 2015x2016\Rightarrow\frac{1}{2014x2015}>\frac{1}{2015x2016}\Rightarrow A< B\)

4/35 cau nay minh tung lam rui

bằng 1 

    \(\frac{2012+2013x2014}{2014x2015-2016}\)

= \(\frac{2012+4054182}{4058210-2016}\)

= \(\frac{4056194}{4056194}\)

= \(\frac{1}{1}\)

= \(1\)

Answer : \(1\)

\(\frac{2012+2013.2014}{2014.2015-2016}\)

\(=\frac{2012+2013.2014}{2014.\left(2013+2\right)-2016}\)

\(=\frac{2012+2013.2014}{2014.2013+2014.2-2016}\)

\(=\frac{2012}{4028-2016}\)

\(=\frac{2012}{2012}\)

\(=1\)

x la dau nhan ha em?

x là nhân hả bạn

Ta có \(\frac{2011}{2012}>\frac{2011}{2012+2013}\) 

          \(\frac{2012}{2013}>\frac{2012}{2012+2013}\)

\(\Rightarrow\frac{2011}{2012}+\frac{2012}{2013}>\frac{2011+2012}{2012+2013}\)(ĐPCM)

Học tốt 

\(\frac{2012+2013x2014}{2014x2015-2016}\)^{\(=\frac{2012+2013x2014}{2014x\left(2013+2\right)-2016}\)}

                                                       ^{\(=\frac{2012+2013x2014}{2014x2013+4028-2016}\)}

                                                        ^{\(=\frac{2012+2013x2014}{2014x2013+2012}\)}

                                                        ^\(=1\)

\(\frac{2012+2013x2014}{2014x2015-2016}\)

= \(\frac{2012+2013x2014}{2014x\left(2013+2\right)-2016}\)

= \(\frac{2012+2013x2014}{2014x2013+4028-2016}\)

= \(\frac{2012+2013x2014}{2014x2013+2012}\)

= 1

giải giúp mk với mk đang cần gấp lắm!!! Mong các bạn giúp đỡ mk với!!!

\(A=\frac{2010}{2009}+\frac{2011}{2010}+\frac{2012}{2011}+\frac{2009}{2012}=\left(1+\frac{1}{2009}\right)+\left(1+\frac{1}{2010}\right)+\left(1+\frac{1}{2011}\right)+\frac{2009}{2012}>\left(1+\frac{1}{2012}\right)+\left(1+\frac{1}{2012}\right)+\left(1+\frac{1}{2012}\right)+\frac{2009}{2012}=\left(1+1+1\right)+\left(\frac{1}{2012}+\frac{1}{2012}+\frac{1}{2012}+\frac{2009}{2012}\right)=3+1=4\)Vì 1/2009,1/2010,1/2011>1/2012

Vậy A>4

a) ta có: \(1-\frac{21}{22}=\frac{1}{22};1-\frac{2011}{2012}=\frac{1}{2012}\)

\(\Rightarrow\frac{1}{22}>\frac{1}{2012}\)

\(\Rightarrow1-\frac{21}{22}>1-\frac{2011}{2012}\Rightarrow\frac{21}{22}< \frac{2011}{2012}\)

b) ta có: \(\frac{31}{95}=0,32;\frac{2012}{6035}=0,33\)

=> 0,32 < 0,33

=> 31.95 < 2012/6035

b) \(\frac{21}{22}\)<  \(\frac{2011}{2012}\)

c) \(\frac{31}{95}\) <   \(\frac{2012}{6035}\)

chúc bạn học tốt.