a; => \(3^x+3^x.3+3^x.3^2=1053\)

=> \(3^x.\left(1+3+3^2\right)=1053\)

=> \(3^x.13=1053\)

=> \(3^x=81\)

=> \(3^x=3^4\)

=> x=4

b; => (x-1)^2.(x-1)=(x-1)^2

=> (x-1)^2.(x-1)-(x-1)^2=0

=> (x-1)^2.[(x-1)^2-1)=0

\(\hept{\begin{cases}x-1=0\\x-1=1\\x-1=-1\end{cases}}\)

=> \(\hept{\begin{cases}x=1\\x=2\\x=0\end{cases}}\)

Đề đúng là 3^x+3^x+1+3^x+2=1053

\(\Rightarrow3^x\left(1+3^1+3^2\right)=1053\)

\(\Rightarrow3^x\cdot13=1053\)

\(\Rightarrow3^x=81\)

\(\Rightarrow3^x=3^4\)

\(\Rightarrow x=4\)

Đề bài phải là :

          \(3^x+3^{x+1}3^{x+2}=1053\)

          \(3^x+3^x.3+3^x.3^2=1053\)

          \(3^x.\left(1+3+3^2\right)=1053\)

          \(3^x.\left(1+3+9\right)=1053\)

          \(3^x.13=1053\)

          \(3^x=1053:13\)

          \(3^x=81\)   

          \(3^x=3^4\)

          \(x=4\)

Chúc bạn học tốt ngu vip

a, \(2.x^x=10.3^{12}+8.27^4\)

\(2.x^x=10.3^{12}+8.3^{12}\)

\(2.x^x=3^{12}.\left(10+8\right)\)

\(2.x^x=3^{12}.18\)

\(2.x^x=3^{12}.2.3^3\)

\(2.x^x=3^{15}.2\)

\(x^x=3^{15}\)( Hình như sai đề )

b,\(3^{2x+2}=9^{x+3}\)

\(3^{2x+2}=3^{2x+3}\)

câu b Sai đề

\(a,3x+17x=340\)

\(x\left(17+3\right)=340\)

\(x20=340\)

\(x=340:20=17\)

\(b,\left|2x+1\right|=3\\ \Rightarrow\left[{}\begin{matrix}2x+1=3\\2x+1=-3\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=3-1=2\\2x=-3-1=-4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=-2\end{matrix}\right.\)

\(c,3^x+3^{x+1}+3^{x+2}=1053\\ 3^x\left(1+3+9\right)=1053\\ 3^x.13=1053\\ 3^x=1053:13=81=3^4\\ \Rightarrow x=4\)

3^x+2+3^x+1+3^x < 1053

3^x(3²+3+1) < 1053

3^x . 13 < 81 . 13

=> 3^x < 81

=> 3^x < 3⁴

=> x < 4

On rồi                            

Ta có 3^x + 3^{x + 1} + 3^{x + 2} = 1053

=> 3^x(1 + 3¹ + 3²) = 1053

=> 3^x(1 + 3 + 9) = 1053

=> 3^x . 13 = 1053

=> 3^x = 1053 : 13 = 81

=> x = 4

3 ^x  + 3 ^x+1 + 3 ^x+2 = 1053

3^x+3^x.3¹+3^x.3²=1053

3^x(1+3¹+3²)=1053

3^x.(1+3+9)=1053

3^x.13=1053

3^x=1053:13

3^x=81

3^x=3⁴

=>x=4

a) \(x +(x + 1) + (x + 2) + ... + (x +30) = 620\)

\(=\left(x+x+...+x+x\right)+\left(1+2+...+30\right)\)

\(=31x+465=620\)

\(=31x=620-465\)

\(=31x=155\)

\(=x=155\div31\)

\(x=5\)

b) \(2+4+6+8+....+2x = 210\)

\(\Rightarrow2.1+2.2+2.3+2.4+...+2.x\)

\(\Rightarrow2.\left(2+4+6+8+...+x\right)=210\)

\(\Rightarrow2+4+6+8+x=210\div2\)

\(\Rightarrow2+4+6+8+...+x=105\)

\(\Rightarrow x=14\)

sao đến 2+4+6+8+...+x = 105 lại => x=14 được bạn

Ta có:

3^x+3^x+1+3^x+2 =1053

=>3^x+3^x.3+3^x.3²=1053

=>3^x.(1+3+3²)=1053

=>3^x.13=1053

=>3^x =81

=>3^x=3⁴

=>x=4

Vậy x=4

các bạn làm ơn giúp mk với mk đang gấp lắm