a) \(\left(2x+1\right)^3=125\)

\(\Rightarrow2x+1=5\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=2\)

Vậy \(x=2\)

b) \(1999^{2x-6}=1\)

\(\Rightarrow1999^{2x-1}=1999^0\)

\(\Rightarrow2x-1=0\)

\(\Rightarrow2x=1\)

\(\Rightarrow x=\frac{1}{2}\)

Vậy \(x=\frac{1}{2}\)

c) \(x^{2002}=x\)

\(\Rightarrow x^{2002}-x=0\)

\(\Rightarrow x.\left(x^{2001}-1\right)=0\)

\(\Rightarrow x=0\) hoặc \(x^{2001}-1=0\)

+) \(x=0\)

+) \(x^{2001}-1=0\Rightarrow x^{2001}=1\Rightarrow x=1\)

Vậy \(x\in\left\{0;1\right\}\)

d) \(\left(x-1\right)^2=9\)

\(\Rightarrow x-1=\pm3\)

+) \(x-1=3\Rightarrow x=4\)

+) \(x-1=-3\Rightarrow x=-2\)

Vậy \(x\in\left\{4;-2\right\}\)

e) \(\left(2x-3\right)^2=81\)

\(\Rightarrow2x-3=\pm9\)

+) \(2x-3=9\Rightarrow2x=12\Rightarrow x=6\)

+) \(2x-3=-9\Rightarrow2x=-6\Rightarrow x=-3\)

Vậy \(x\in\left\{6;-3\right\}\)

Các phần khác làm tương tự

Dễ nhưng bận r

3^ x . 3^ 2= 729

3^ x  . 9        = 729

3^ x               = 729: 9

3^x                 =81 

vậy    x            = 3^3

5^ x . 625 = 3125

5^x           = 3125:625

5^x            =   5

vậy x          = 1

( 2x+1 )^ 3 = 27

( 2x+1) ^ 3 = 3^3

vậy 2x+1 =  3

  vậy x = 0         

d, \(=>\left(\frac{4}{5}\right)^{2x+7}=\left(\frac{4}{5}\right)^4.\)

=> \(2x+7=4\) 

=> 2x= -3

=> x=-3/2     . Vậy x=-3/2

e, => \(\frac{7^x.7^2+7^x.7+7^x}{57}=\frac{5^{2x}+5^{2x}.5+5^{2x}.5^2}{131}.\)

=> \(\frac{7^x\left(7^2+7+1\right)}{57}=\frac{5^{2x}\left(1+5+5^2\right)}{131}\)

= > \(\frac{7^x.57}{57}=\frac{5^{2x}.131}{131}\)

=> \(7^x=5^{2x}\)

Đến đoạn này là mik nghĩ không ra nhé

Cô làm tiếp giúp Linh Đan:

\(7^x=5^{2x}\Rightarrow7^x=25^x\Rightarrow\frac{7^x}{25^x}=1\Rightarrow\left(\frac{7}{25}\right)^x=1\Rightarrow x=0\)

a) \(\left(x-4\right)^2=\left(x-4\right)^4\)

\(\Rightarrow\left(x-4\right)^2-\left(x-4^4\right)=0\)

\(\Rightarrow\left(x-4\right)^2.\left[1-\left(x-4\right)^2\right]=0\)

\(\Rightarrow\left[{}\begin{matrix}\left(x-4\right)^2=0\\1-\left(x-4\right)^2=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x-4=0\\\left(x-4\right)^2=1^2\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x-4=0\\x-4=1\\x-4=-1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=4\\x=5\\x=3\end{matrix}\right.\)

a, (x-1) . 0,5 = 7,5 : (x-1) 

=> = ( x  - 1 ) 0,5 = \(\frac{x-1}{2}\)

\(=\frac{7,5}{x-1}=\frac{15}{2\left(x-1\right)}\)

=> x = - 1 \(\sqrt{15}\)

x = \(\sqrt{15+1}\)

đề sao sao ý

a) x(1+2+...+30) = 11625

x.465 = 11625

x = 25

5^2.x . 55^x = 625

=> 25.x.55^x=5^4

=> x.55^x=25

Giải ra ta được kết quả : 2113/2500

Giúp mik với

2.
a) (2x + 1)³ = 125
    (2x + 1)³ = 5³
     2x + 1    = 5
     2x          = 5 - 1
     2x          = 4
       x          = 4:2
       x          = 2
Vậy x = 2
b) 5^x+1 = 5⁴
    x + 1 = 4
    x       = 4 - 1 
    x       = 3
Vây x = 3

a) \(A=1.2+2.3+3.4+...+98.99+99.100\)

\(3A=1.2.3+2.3.4+3.4.3+...+99.100.3\) 

\(3A=1.2.\left(3-0\right)+2.3.\left(4-1\right)+3.4.\left(5-2\right)....99.100.\left(101-98\right)\) 

\(3A=\left(1.2.3+2.3.4+3.4.5+...+99.100.101\right)-\left(0.1.2+1.2.3+2.3.4+...+98.99.100\right)\)

\(3A=99.100.101-0.1.2\) 

\(3A=999900-0\)

\(3A=999900\)

\(A=999900:3\)

\(\Rightarrow A=333300\)