99 - 3(x + 17) = 45

=> 3(x + 17) = 99 - 45

=> 3x + 51 = 54

=> 3x = 54 - 53

=> 3x = 3

=> x = 3 : 3

=> x = 1

vậy_

a,99-3x-51=45

3x=45+51-99

3x=-3

x=-1

b,x⁵:8=4

x⁵=32

x=2

c,3.x³=375

x³=125

x=5

d,12.x-33=3⁵

12x=276

x=23

e,4x⁵=128

x⁵=32

x=2

g,2^x:4=16

2^x=64

x=6

a) \(3\left[35+\left(x+10\right)\right]-375=0\)

\(3\left(35+x+10\right)=375\)

\(x+45=125\)

\(x=80\)

b) \(2\left|x\right|-\left(-5\right)=7\)

\(2\left|x\right|+5=7\)

\(2\left|x\right|=2\)

\(\left|x\right|=1\)

\(\Rightarrow x\in\left\{1;-1\right\}\)

a) 3.[35+(x+10)]-375=0

   3.[35+(x+10)]       = 0+375

   3.[35+(x+10)]       = 375

      35+(x+10)         = 375:3

      35+(x+10)         = 125

            x+10          = 125-35

            x+10          = 90

              x              = 90-10

              x              = 80

Vậy x=80

\(2^x.4=128\)

\(2^x=128:4\)

\(2^x=32\)

\(\Leftrightarrow2^x=2^5\Leftrightarrow x=5\)

\(x^{15}=x\Leftrightarrow x\in\left\{-1;0;1\right\}\)

\(\left(2x+1\right)^3=125\)

\(\Leftrightarrow\left(2x+1\right)^3=5^3\)

\(\Leftrightarrow2x+1=5\)

\(\Leftrightarrow2x=4\)

\(\Leftrightarrow x=2\)

\(\left(x-5\right)^6=\left(x-5\right)^4\)

\(\Leftrightarrow\hept{\begin{cases}x-5=-1\\x-5=0\\x-5=1\end{cases}}\Leftrightarrow\hept{\begin{cases}x=4\\x=5\\x=6\end{cases}}\)

\(\text{Vậy:}\)\(x\in\left\{4;5;6\right\}\)

\(2^x.4=128\Rightarrow2^x=32\Rightarrow2^x=2^5\Rightarrow x=5.\)

\(x^{15}=x\Rightarrow\orbr{\begin{cases}x=\pm1\\x=0\end{cases}}\)

       \(\left(2x+1\right)^3=125\)

<=>  \(\left(2x+1\right)^3=5^3\)

<=>   \(2x+1=5\)

<=>   \(x=2\)

        \(\left(x-5\right)^6=\left(x-5\right)^4\)

<=>   \(\left(x-5\right)^6-\left(x-5\right)^4=0\)

<=>    \(\left(x-5\right)^4.\left[\left(x-5\right)^2-1\right]=0\)

<=>     \(\orbr{\begin{cases}\left(x-5\right)^4=0\\\left(x-5\right)^2-1=0\end{cases}}\)

<=>      \(\orbr{\begin{cases}x-5=0\\\left(x-5\right)^2=1\end{cases}}\)

Giải ra được x = 5 ; x = 6 ; x = 4 .

a.

2^x . 4 = 128

2^x = 128 : 4

2^x = 32

2^x = 2⁵

x = 5

b.

x¹⁵ = x

Vậy x = 0 hoặc x = 1 hoặc x = -1

c.

(2x + 1)³ = 125

(2x + 1)³ = 5³

2x + 1 = 5

2x = 5 - 1

2x = 4

x = 4 : 2

x = 2

d.

(x - 5)⁴ = (x - 5)⁶

TH1:

x - 5 = 0

x = 5

TH2:

x - 5 = -1

x = -1 + 5

x = 4

TH2:

x - 5 = 1

x = 1 + 5 

x = 6

Vậy x = 5 hoặc x = 4 hoặc x = 6

Chúc bạn học tốt ^^ 

a) \(2^x.4=128\)

=> \(2^x=32\) => \(2^x=2^5\) => x = 5

b) \(x^{15}=x\) => x = 1 hoặc x = 0

c) \(\left(2x+1\right)^3=125\)

=> \(\left(2x+1\right)^3=5^3\) => 2x + 1 = 5 => x = 2

d) \(\left(x-5\right)^4=\left(x-5\right)^6\) 

=> x - 5 = 0 hoặc x - 5 = 1

=> x = 5 hoặc x= 6

Chúc bạn làm bài tốt

a) 2^x.2^4=128

=>2^x.2^2=2^7

=>2^x=2^7:2^2

=>2^x=2^5

=>x=5

b)x^15=x

=>x^15-x=0

=>x(x^16-x)=0

=>2 trượng hợp:x=0 và x^16-1=0(x^16-1=0 cx 2 th nha)

b),d),e) như nhau nha!

c) dễ rồi

\(a)2^x\cdot4=128\)

\(\Rightarrow2^x=\frac{128}{4}\)

\(\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

\(b)x^{15}=x\)

\(\Rightarrow x^{15}-x=0\)

\(\Rightarrow x(x^{14}-1)=0\)

\(\Rightarrow\hept{\begin{cases}x=0\\x^{14}-1=0\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x=0\\x^{14}=1\end{cases}\Rightarrow}\hept{\begin{cases}x=0\\x=1\end{cases}}\)

\(c)(2x+1)^3=125\)

\(\Rightarrow(2x+1)^3=5^3\)

\(\Rightarrow2x+1=5\)

\(\Rightarrow2x=5-1\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=4:2=2\)

\(d)(x-5)^4=(x-5)^6\)

\(\Rightarrow(x-5)^6-(x-5)^4=0\)

\(\Rightarrow(x-5)^4\cdot\left[(x-5)^2-1\right]=0\)

\(\Rightarrow\orbr{\begin{cases}(x-5)^4=0\\(x-5)^2-1=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=6\end{cases}}\)

\(e)(2x-15)^5=(2x-15)^3\)

\(\Rightarrow(2x-15)^5-(2x-15)^3=0\)

\(\Rightarrow(2x-15)^3-\left[(2x-15)^2-1\right]=0\)

\(\Rightarrow\orbr{\begin{cases}(2x-15)^3=0\\(2x-15)^2-1=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=\varnothing\\x=8\end{cases}}\)

Chúc bạn hoc tốt :>

\(5^{x-1}=125\)

\(5^{x-1}=5^3\)

\(\Rightarrow x-1=3\)nên x = 4