\(1:\frac{1}{2}:\frac{2}{3}:\frac{3}{4}:\frac{4}{5}:\frac{5}{6}:\frac{6}{7}:\frac{7}{8}=........\)

\(\frac{8}{1}+\frac{7}{2}+\frac{6}{3}+\frac{5}{4}+\frac{4}{5}+\frac{3}{6}+\frac{2}{7}+\frac{1}{8}\)

\(1\frac{1}{8}\)x\(1\frac{6}{3}\)=?

\(3\frac{4}{5}\)+\(1\frac{4}{5}\)=?

\(4\frac{3}{7}\):\(3\frac{7}{5}\)=?

\(3\frac{9}{1}\)-\(5\frac{6}{5}\)=?

\(\frac{10+\frac{9}{2}+\frac{8}{3}+\frac{7}{4}+ \frac{6}{5}+\frac{5}{6}+\frac{4}{7}+\frac{3}{8}+\frac{2}{9}+\frac{1}{10}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}+\frac{1}{11}}\)

\(1\frac{1}{3}\)x \(2\frac{1}{4}\)x\(3\frac{1}{5}\)x\(4\frac{1}{6}\)x\(5\frac{1}{7}\)x\(6\frac{1}{8}\)x\(7\frac{1}{9}\)x\(8\frac{1}{10}\)

Tính:

a,\(\frac{\left(3+\frac{1}{6}\right)-\frac{2}{5}}{\left(5-\frac{1}{6}\right)+\frac{7}{10}}\)

b,\(\frac{\left(4,08-\frac{2}{25}\right):\frac{4}{17}}{\left(6\frac{5}{9}-3\frac{1}{4}\right)x2\frac{2}{7}}\)

c,\(\frac{2-\frac{1}{4}+\frac{1}{3}-\frac{3}{5}}{3-\frac{1}{5}-\frac{5}{3}}\)

So sánh \(A\)với\(13\),biết rằng:

\(A=\frac{13}{15}+\frac{7}{5}+\frac{3}{4}+\frac{1}{5}+\frac{1}{7}+\frac{19}{20}+\frac{5}{4}+\frac{1}{3}+\frac{1}{6}+\frac{1}{13}+\frac{17}{23}+\frac{9}{8}+\frac{2}{5}+\frac{1}{7}+\frac{1}{25}+\frac{3}{2}+\frac{1}{8}+\frac{1}{19}+\frac{1}{9}+\frac{1}{97}\)