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B=\(\frac{2002.\left(14+1\right)-1}{2001+2002.14}\)=\(\frac{2002.14+2001}{2001+2002.14}\)=1
Giải hộ mình câu này với:
(215/216+3971/3972-1/5)x(-9/35+2/5-1/7)=..........................?
\(\frac{23}{12}\)
\(\frac{314}{105}\)
\(\frac{59}{60}\)
\(\frac{199}{90}\)
\(\frac{1}{18}\)
\(\frac{13}{36}\)
\(\frac{4}{221}\)
\(\frac{4}{85}\)
a, \(\frac{1}{2}\)+ \(\frac{1}{3}\)+ \(\frac{1}{5}\)+ \(\frac{1}{6}\)
= (\(\frac{1}{2}+\)\(\frac{1}{3}+\)\(\frac{1}{6}\)) + \(\frac{1}{5}\)
= 1 + \(\frac{1}{5}\)
= \(\frac{6}{5}\)
b, mk chịu
a) \(\frac{1}{2}+\frac{1}{3}+\frac{1}{5}+\frac{1}{6}=\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\right)+\frac{1}{5}\)
\(=\left(\frac{3}{6}+\frac{2}{6}+\frac{1}{6}\right)+\frac{1}{5}\)
\(=1+\frac{1}{5}\)
\(=\frac{6}{5}\)
b) \(\frac{4}{6}+\frac{7}{13}+\frac{17}{9}+\frac{19}{13}-\frac{8}{9}+\frac{14}{6}=\left(\frac{4}{6}+\frac{14}{6}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)+\left(\frac{17}{9}-\frac{8}{9}\right)\)
\(=\frac{18}{6}+\frac{26}{13}+\frac{9}{9}=3+2+1=6\)
Đặt biểu thức trên là A ta có:
A = \(\frac{1}{3}\)+ \(\frac{1}{6}\)+ \(\frac{1}{12}\)+ \(\frac{1}{24}\)+ \(\frac{1}{48}\)+ \(\frac{1}{96}\)
A x 3 = \(1\)+ \(\frac{1}{2}\)+ \(\frac{1}{4}\)+ \(\frac{1}{8}\)+ \(\frac{1}{16}\)+ \(\frac{1}{32}\)
A x 3 = \(1\)+ \(1\)- \(\frac{1}{2}\)+ \(\frac{1}{2}\)- \(\frac{1}{4}\)+ \(\frac{1}{4}\)- \(\frac{1}{8}\)+ \(\frac{1}{8}\)- \(\frac{1}{16}\)+ \(\frac{1}{16}\)- \(\frac{1}{32}\)
A x 3 = 2 - \(\frac{1}{32}\)= \(\frac{63}{32}\)
A = \(\frac{63}{32}\): 3 = \(\frac{63}{96}\)
\(\frac{2}{3}+\frac{5}{8}+\frac{9}{3}:\frac{4}{7}.\left(\frac{2}{6}+\frac{1}{1}\right)\)
\(=\frac{2}{3}+\frac{5}{8}+3:\frac{4}{7}.\left(\frac{1}{3}+1\right)\)
\(=\frac{2}{3}+\frac{5}{8}+\frac{21}{4}.\frac{4}{3}\)
\(=\frac{2}{3}+\frac{5}{8}+7\)
\(=\frac{16}{24}+\frac{15}{24}+7\)
\(=\frac{31}{24}+7\)
\(=\frac{19}{12}\)
Mình không biết đúng hay sai, nhưng mà kết bạn nha!