= 1,02 nha

1 và 2/100=102/100=1.02

Ta có: \(\frac{54}{195}-\frac{1}{2}=\frac{108}{390}-\frac{195}{390}\)

\(=-\frac{87}{390}=-\frac{29}{130}\)

Vậy \(\frac{54}{195}-\frac{1}{2}=-\frac{29}{130}\)

Gửi lời mời đi

\(5-1,5-1\frac{1}{2}\)

=\(5-1,5-1,5\)

=\(5-\left(1,5+1,5\right)\)

=\(5-3\)

=\(2\)

= 5 - 1,5 - 1, 5 = 5 - 3 = 2.

Kết bạn cái đầu bà ý :v !!

\(\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\right).100-\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=89\)

\(\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right).100-\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=89\)

\(\left(1-\frac{1}{10}\right).100-\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=89\)

\(90-\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=89\)

\(\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=1\)

\(\frac{5}{2}:\left(x+\frac{266}{100}\right)=\frac{1}{2}\Rightarrow x+\frac{266}{100}=5\Rightarrow x=\frac{117}{50}\)

Vậy x = 117/50

Ta có:

 \(\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{9.10}\right).100\\ =\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right).100\)

   \(=\left(1-\frac{1}{10}\right).100\)    

   \(=\frac{9}{10}.100\)

   = 90

Khi đó đề bài sẽ thành : \(90-\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=89\)

                                \(\Rightarrow\left[\frac{5}{2}:\left(x+\frac{266}{100}\right)\right]:\frac{1}{2}=1\)

                                \(\Rightarrow\frac{5}{2}:\left(x+\frac{266}{100}\right)=\frac{1}{2}\)

                                \(\Rightarrow x+\frac{266}{100}=5\)

                               \(\Rightarrow x=\frac{117}{50}\)

Vậy \(x=\frac{117}{50}\)

\(2\frac{4}{3}+\frac{4}{12}=\frac{2.3+4}{3}+\frac{4}{12}=\frac{10}{3}+\frac{4}{12}=\frac{40}{12}+\frac{4}{12}=\frac{44}{12}=\frac{11}{3}\)

\(2\frac{4}{3}=\frac{10}{3}\)

\(\frac{10}{3}+\frac{4}{12}=\frac{120}{36}+\frac{12}{36}\)

\(=\frac{132}{36}=\frac{22}{6}=\frac{11}{3}\)

\(2\frac{1}{2}:\frac{3}{4}=\frac{5}{2}:\frac{3}{4}\)

= 5/2 x 4/3

=\(\frac{20}{6}\)

M.n tk giùm em vs ạ !! ^_^

\(12\frac{3}{7}\%+12\frac{5}{7}\%=\frac{176}{7}\%\)

\(đổi9\frac{3}{2}=\frac{21}{2}\)

\(\frac{9}{2}+\frac{21}{2}=\frac{30}{2}=15\)

\(=15\)

= 9/2 + 21/2

=15

\(12\frac{4}{5}\)=\(\frac{64}{5}\).

Ta có :

\(\frac{64}{5}+\frac{4}{5}=\frac{68}{5}\)

\(12\frac{4}{5}+\frac{4}{5}=\frac{64}{5}+\frac{4}{5}=\frac{68}{5}\)