a)   \(x-\frac{4}{5}=\frac{5}{7}\)

                  \(x=\frac{5}{7}+\frac{4}{5}=\frac{53}{35}\)

b)   \(5x=-\frac{1}{5}\)

        \(x=-\frac{1}{5}:5=-\frac{1}{25}\)

c)   \(\frac{5}{3}-x=7+\frac{4}{5}\)

      \(\frac{5}{3}-x=\frac{39}{5}\)

                  \(x=\frac{5}{3}-\frac{39}{5}=-\frac{92}{15}\)

d)    \(-\frac{5}{11}+2x=\frac{7}{22}\)

                        \(2x=\frac{7}{22}+\frac{5}{11}\)

                        \(2x=\frac{17}{22}\)

                          \(x=\frac{17}{22}:2\)

                           \(x=\frac{17}{44}\)

       \(x=-\frac{1}{5}:5\)

NÈ BẠN!!!

a) \(x-\frac{4}{5}=\frac{5}{7}\)

\(x=\frac{5}{7}+\frac{4}{5}=\frac{25}{35}+\frac{28}{35}=\frac{53}{35}\)

b) \(5x=-\frac{1}{5}+\frac{11}{5}\)

\(5x=2\)

\(x=\frac{2}{5}\)

c)\(\frac{5}{3}-x=7\)

\(x=\frac{5}{3}-7=\frac{5}{3}-\frac{21}{3}=-\frac{16}{3}\)

d) \(-\frac{5}{11}+2x=\frac{7}{22}\)

\(2x=\frac{7}{22}-\frac{-5}{11}=\frac{7}{22}-\frac{-10}{22}=\frac{17}{22}\)

\(x=\frac{17}{22}:2=\frac{17}{22}\cdot\frac{1}{2}=\frac{17}{44}\)

K CHO MÌNH NHA!!!

a)  -1/8 -2x/5-1/3=3

-2x/5=3+1/8+1/3

-2x/5=83/24

-2x=(83×5)/24=415/24

x = (415÷-2)/24= -415/48

b) -7/3 -(25/6 -4/3+ 3/2)

= -7/3 -13/3 = -20/3

ai ma co 10 k ban chac ban phai lap chuc nink thui

i don't know i mới học lớp 5

bn eie mik lớp 6 nha bn

a) \(x^3-\frac{4}{25}x=0\)

\(\Leftrightarrow x\left(x+\frac{2}{5}\right)\left(x-\frac{2}{5}\right)=0\)

<=> x = 0

Xét 2 trường hợp: 

\(\Leftrightarrow x+\frac{2}{5}=0\)

      \(x=0-\frac{2}{5}\)

      \(x=-\frac{2}{5}\)

\(\Leftrightarrow x-\frac{2}{5}=0\)

      \(x=0+\frac{2}{5}\)

      \(x=\frac{2}{5}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=\pm\frac{2}{5}\end{cases}}\)

b) \(\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)

\(=\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{4}{3}\)

\(=\frac{13}{40}:\frac{4}{3}\)

\(=\frac{39}{120}=\frac{13}{40}\)

c) \(4\left(\frac{-1}{2}\right)^3-2\left(\frac{-1}{2}\right)^2+3\left(\frac{-1}{2}\right)-1\left(\frac{-1}{2}\right)^0\)

\(=4\left(\frac{-1}{2}\right)^3-2\left(\frac{-1}{2}\right)^3+3\left(\frac{-1}{2}\right)-1.1\)

\(=-\frac{1}{2}-\frac{1}{2}-\frac{3}{2}-1.1\)

\(=-\frac{5}{2}-1\)

\(=-\frac{7}{2}\)

a

\(5\frac{4}{7}:x+=13\)

\(\frac{39}{7}:x=13\)

\(x=\frac{39}{7}:13\)

\(x=\frac{3}{7}\)

\(\frac{4}{7}x=\frac{9}{8}-0,125\)

\(\frac{4}{7}x=1\)

\(x=1:\frac{4}{7}\)

\(x=\frac{7}{4}=1\frac{3}{4}\)

a) \(\frac{2}{5}:\left(2x+\frac{3}{4}\right)=-\frac{7}{10}\)

=> \(2x+\frac{3}{4}=-\frac{7}{10}:\frac{2}{5}\)

=> \(2x+\frac{3}{4}=-\frac{7}{4}\)

=> \(2x=\frac{-7}{4}-\frac{3}{4}\)

=> \(2x=-\frac{5}{2}\)

=> \(x=\frac{-5}{2}:2\)

=> \(x=\frac{-5}{4}\)

b) \(\frac{x+1}{3}=\frac{2-x}{2}\)

\(\Rightarrow2\left(x+1\right)=3\left(2-x\right)\)

\(\Rightarrow2x+2=6-3x\)

\(\Rightarrow2x-3x=6-2\)

\(\Rightarrow-x=4\)

\(\Rightarrow x=4\)

c) \(\left|x-\frac{3}{5}\right|.\frac{1}{2}-\frac{1}{5}=0\)

\(\Rightarrow\left|x-\frac{3}{5}\right|.\frac{1}{2}=\frac{1}{5}\)

\(\Rightarrow\left|x-\frac{3}{5}\right|=\frac{1}{5}:\frac{1}{2}\)

\(\Rightarrow\left|x-\frac{3}{5}\right|=\frac{2}{5}\)

\(\Rightarrow\orbr{\begin{cases}x-\frac{3}{5}=\frac{2}{5}\\x-\frac{3}{5}=-\frac{2}{5}\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=\frac{3}{5}+\frac{2}{5}\\x=\frac{3}{5}+-\frac{2}{5}\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=1\\x=\frac{1}{5}\end{cases}}\)

Vậy \(\orbr{\begin{cases}x=1\\x=\frac{1}{5}\end{cases}}\)

d) \(x^2-4x=0\)

Ta có : \(x^2-4x=0\)

\(\Rightarrow xx-4x=0\)

\(\Rightarrow x\left(x-4\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x-4=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=0+4\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=4\end{cases}}\)

Vậy \(\orbr{\begin{cases}x=0\\x=4\end{cases}}\)

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