a) 3y + 2y = 850

5y = 850

y = 850 : 5

y = 170

Ps: Ko nên tự trả lời ,tự !

a)3y+2y=850

5y=850

y=850/5

y=170

1/2  x   y + 1/3   x y +  1/4   x y  = 11/4 

  y x ( 1/2 + 1/3 + 1/4 )               = 11/4 

  y x 13/12                                = 11/4 

 y                                             = 11/4 : 13/12 

y                                              = 11/4  x 12/13

y                                               = 33/13  

^^ Học tốt! 

\(\frac{1}{2}\times Y+\frac{1}{3}\times Y+\frac{1}{4}\times Y=\frac{11}{4}\)

\(3Y=\frac{11}{4}\div\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right)\)

\(3Y=\frac{33}{13}\)

\(Y=\frac{33}{13}\div3\)

\(Y=\frac{11}{13}\)

~ Chúc bạn học tốt 

KO TRẢ LỜI ĐƯỢC À

\(\frac{2,4\cdot y-0,23}{y}=1,44\div1,2\)

\(\frac{2,4\cdot y-0,23}{y}=1,2\)

Y - \(\frac{3}{4}=6\)x   \(\frac{3}{8}\)

Y - \(\frac{3}{4}\)= \(\frac{9}{4}\)

Y            = \(\frac{9}{4}+\frac{3}{4}\)

Y            = \(\frac{12}{4}\)

 Y           = 3
 

y  -  3/4              = 9/4

y                        = 9/4 + 3/4

y                        = 3

ai thấy đúng thì tck cho mình nha

bài 2 

a] = 3 x \(\frac{4343}{7171}\)= \(\frac{17372}{7171}\)= \(\frac{172}{71}\)

b] = \(\frac{1}{33}\)x \(\frac{44}{7}\)= \(\frac{1}{3}\)x \(\frac{4}{7}\)=\(\frac{4}{21}\)

bài 1 

a] y là 9

b] <=> 64y + 36y = 700 - 75 - 225

<=> 100y = 400

<=> y = 4

trên lớp cô sửa rồi nên mình giải luôn:

1) Tìm y

a) y3 + 3y = 12 x 11

    y3 + 3y = 132

    y x 10 + 3 + 3 x 10 + y = 132

   ( y x 10 + y ) + ( 3 x 10 + 3 ) = 132

     11 x y + 33 = 132 

     11 x y = 132 - 33

     11 x y = 99

            y = 99 : 11

            y = 9

b) 64 x y + 225 = 700 - 75 - 36 x y

    64 x y + 225 = 625 - 36 x y

    64 x y + 36 x y = 625 -225

    64 x y + 36 x y = 400

    ( 64 + 36 ) x y = 400

    100 x y = 400

              y =  400 : 100

              y = 4

2) Tính

a) \(\frac{4343}{7171}+\frac{4343}{7171}+\frac{4343}{7171}+\frac{4343}{7171}\)

\(=\frac{4343}{7171}\times4\)

\(=\frac{43}{71}\times4\)

\(=\frac{172}{71}\)

b) A = \(\frac{1}{33}\times\left(\frac{33}{12}+\frac{3333}{2020}+\frac{333333}{303030}+\frac{33333333}{42424242}\right)\)

   Ta có:

   \(\frac{3333}{2020}=\frac{3333:101}{2020:101}=\frac{33}{20}\)

   \(\frac{333333}{303030}=\frac{333333:10101}{303030:10101}=\frac{33}{30}\)

  \(\frac{33333333}{42424242}=\frac{33333333:1010101}{42424242:1010101}=\frac{33}{42}\)

   A = \(\frac{1}{33}\times\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}\right)\)

   A = \(\frac{1}{33}\times33\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\)

  A = 1 x \(\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\)

  A = 1 x \(\left(\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}\right)\)

  A = 1 x \(\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)

  A = 1 x \(\left(\frac{1}{3}-\frac{1}{7}\right)\)

  A = 1 x \(\left(\frac{7}{21}-\frac{3}{21}\right)\)

  A = 1 x \(\frac{4}{21}\)

  A = \(\frac{4}{21}\)

\(\frac{7}{8}\)x Y = 3 - \(\frac{1}{2}\)

\(\frac{7}{8}\)x Y = \(\frac{5}{2}\)

            Y = \(\frac{20}{7}\)

y3 + 3y = 12 x 11

y3 + 3y = 132

y x 10 + 3 + 30 +y = 132

y x 11 + 33 = 132

y x 11 = 132 - 33

y x 11 = 99

y = 9

tick cho mình nha!!!!!

y3+3y=132

 y=9

được 39 + 93 = 132

tích nha bạn cảm ơn !!!!!!!!!!!