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201,7 x 8,02 + 201,7 : \(\frac{4}{3}\)+ 201,7 x 1,98 - 0,75 x 201,7
= 201,7 x 8,02 + 201,7 x \(\frac{3}{4}\)+ 201,7 x 1,98 - 0,75 x 201,7
= 201,7 x ( 8.02 + \(\frac{3}{4}\)+ 1,98 - 0,75)
= 201,7 x ( 8,02 + 1,98, + \(\frac{3}{4}\)- 0,75)
= 201,7 x 10
= 2017
a) \(\frac{8}{11}-\frac{28}{99}-\frac{14}{99}=\frac{72}{99}-\frac{28}{99}-\frac{14}{99}=\frac{30}{99}=\frac{10}{33}\)
b) \(5\frac{3}{4}-3\frac{1}{2}=\)\(\frac{23}{4}-\frac{7}{2}=\frac{23}{4}-\frac{14}{4}=\frac{9}{4}\)
A) 8/11- 28/99- 14/99 8/11=72/99 (72/99 +28/99)-14/99 =100/99-14/99 =86/99
75/100 + 3/4 x 29 + 75% x 30 + 0,75 x 40
= 0,75 + 0,75 x 29 + 0,75 x30 + 0,75 x 40
= 0,75 x ( 1 + 29 + 30 + 40 )
= 0,75 x 100
=75
\(\frac{75}{100}+\frac{3}{4}\times29+75\%\times30+0,75\times40\)
\(=\frac{75}{100}\times1+\frac{3\times25}{4\times25}\times29+\frac{75}{100}\times30+\frac{0,75}{1}\times40\)
\(=\frac{75}{100}\times1+\frac{75}{100}\times29+\frac{75}{100}\times30+\frac{0,75\times100}{1\times100}\times40\)
\(=\frac{75}{100}\times1+\frac{75}{100}\times29+\frac{75}{100}\times30+\frac{75}{100}\times40\)
\(=\frac{75}{100}\left(1+29+30+40\right)\)
\(=\frac{75}{100}\times100\)
\(=\frac{75}{100}\times\frac{100}{1}\)
\(=\frac{75}{1}\)
\(=75\)
\(=\frac{75\times100}{100\times1}\)
75/100+75%.2+3/4.3+0.75.4
=3/4+3/4.2+3/4.3+3/4.4
=3/4.(1+2+3+4)
=3/4.10
=15/2
=2.5:4/1+0.75x2.5=2.5x0.25+0.75x2.5=2.5(0.25+0.75)=2.5x1=2.5
\(a)101\times0,75-0,75\)
\(=0,75\times(101-1)\)
\(=0,75\times100=75\)
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`b)10:0,5+4:0,25+8:0,125`
\(=10\times2+4\times4+8\times8\)
\(=5\times4+4\times4+4\times16\)
\(=4\times(5+4+16)\)
\(=4\times25=100\)
a)101×0,75−0,75
=0,75\times(101-1)=0,75×(101−1)
=0,75\times100=75=0,75×100=75
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b)10:0,5+4:0,25+8:0,125b)10:0,5+4:0,25+8:0,125
=10\times2+4\times4+8\times8=10×2+4×4+8×8
=5\times4+4\times4+4\times16=5×4+4×4+4×16
=4\times(5+4+16)=4×(5+4+16)
=4\times25=100=4×25=100
a) \(0,75x99+\dfrac{3}{4}=\dfrac{3}{4}x99+\dfrac{3}{4}=\dfrac{3}{4}x\left(99+1\right)=\dfrac{3}{4}x100=75\)
b) \(3,05x8+9,15-3,05=3,05x8+3x3,05-3,05=3,05x\left(8+3-1\right)=3,05x10=30,5\)